\(A=\dfrac{4116-14}{10290-35}=\dfrac{14\times\left(294-1\right)}{35\times\left(294-1\right)}=\dfrac{14}{35}\)

\(B=\dfrac{2929-101}{2\times1919+404}=\dfrac{101\times\left(29-1\right)}{101\times\left(38+4\right)}=\dfrac{29-1}{38+4}=\dfrac{28}{32}=\dfrac{7}{8}\)

a) \(\dfrac{4116-14}{10290-35}=\dfrac{4102}{10255}=\dfrac{2051.2}{2051.5}=\dfrac{2}{5}\)

b) \(\dfrac{2929-101}{2.1919+404}=\dfrac{2929-101}{3838+404}=\dfrac{2828}{4242}=\dfrac{1414.2}{1414.3}=\dfrac{2}{3}\)

Rút gọn :

A= \(\dfrac{4116-14}{10290-35}\)= \(\dfrac{4102}{10255}=\dfrac{4102:2051}{10255:2051}=\dfrac{2}{5}\)

B=\(\dfrac{2929-101}{2.1919+404}=\dfrac{2828}{3838+404}=\dfrac{2828}{4242}=\dfrac{2828:1414}{4242:1414}=\dfrac{2}{3}\)

c) E = \(\dfrac{4116-14}{10290-35}\) và K = \(\dfrac{2929-101}{2.1919+404}\)

E = \(\dfrac{4116-14}{10290-35}\)

E = \(\dfrac{14.\left(294-1\right)}{35.\left(294-1\right)}\)

E = \(\dfrac{14}{35}\)

K = \(\dfrac{2929-101}{2.1919+404}\)

K = \(\dfrac{101.\left(29-1\right)}{101.\left(38+4\right)}\)

K = \(\dfrac{29-1}{34+8}\)

K = \(\dfrac{28}{42}\) = \(\dfrac{2}{3}\)

Ta có : E = \(\dfrac{14}{35}\) và K = \(\dfrac{2}{3}\)

\(\dfrac{14}{35}\) = \(\dfrac{42}{105}\)

\(\dfrac{2}{3}\) = \(\dfrac{70}{105}\)

Vậy E < K

Các câu còn lại tương tự

=4102/10255

=(4102:2051)/(10255:2051)

=2/5

4116 - 14/ 10290 - 35

= 4102/10255

= 4102 : 2051/10255 : 2051

= 2/5

\(\frac{4102}{10255}\)=\(\frac{2}{5}\)

\(\frac{270}{450}=\frac{270:90}{450:90}=\frac{3}{5}\)

\(\frac{26}{156}=\frac{26:26}{156:26}=\frac{1}{6}\)

\(\frac{123123}{237237}=\frac{123123:3003}{237237:3003}=\frac{41}{79}\)

6/3=12/6

B)=0,4 HAY2/5

Rút gọn

a)\(\frac{4116-14}{10290-35}\)

b)\(\frac{2929-101}{21919+404}\)

                                                                                   GIẢI

a)

=\(\frac{4102}{10255}\)

=\(\frac{4102:2051}{10255:2051}\)

=\(\frac{2}{5}\)

b)

=\(\frac{2828}{22323}\)

=\(\frac{2828:7}{22323:7}\)

=\(\frac{404}{3189}\)

A=\(\frac{14.294-14}{35.294-35}=\frac{14.\left(294-1\right)}{35.\left(294-1\right)}=\frac{14}{35}=\frac{2}{5}\)

ƯCLN(4116,35)=7

ƯCLN(14,10290)=14

Nên rút gọn thành: 588-1/735-5

\(\frac{4116-14}{10290-35}=\frac{2}{5}\)